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Thursday, November 28, 2024

Myles Garrett named AFC Defensive Player of the Week

Myles Garrett named AFC Defensive Player of the Week

BEREA, Ohio — Myles Garrett declared himself the No. 1 edge defender in the NFL after Thursday night’s upset of the Steelers, and now he has an AFC Defensive Player of the Week award to show for it.

Garrett, the reigning NFL Defensive Player of the Year, earned the award after recording five tackles, three sacks and one forced fumble during the Browns’ 24-19 victory over the Steelers. All three sacks had a huge impact on the game, with the first an 8-yarder that set kicker Chris Boswell back for a 58-yard attempt that he missed. The second was a strip-sack that led to a field goal, and the third came on a third-down play at the end of the first half to prevent a Hail Mary.

“It’s great,” Kevin Stefanski said. “Individual accolades are tremendous. We want our guys to be recognized. The nice part is it also reflects well on your teammates. So, happy for Myles, and also recognize that it takes everybody to achieve those. But what Myles is doing, play in and play out, game in and game out with the amount of attention that he gets play in and play out is pretty impressive.”

Garrett is the only NFL player to record multiple games with at least three sacks this season, and achieved it in the span of three games. The first was his three-sack outburst against the Chargers. He increased his season total to 10 sacks (tied for third in the NFL) and he is only NFL player to record at least 10 sacks in each of the past seven seasons (2018-24).

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